Question : Directions: In the following question, select the odd letter cluster from the given alternatives.
Option 1: ACFJ
Option 2: RTWA
Option 3: NPSV
Option 4: HJMQ
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Correct Answer: NPSV
Solution :
Let's check the options –
First option:
ACFJ; A + 2 = C; C + 3 = F; F + 4 = J
Second option:
RTWA; R + 2 = T; T + 3 = W; W + 4 = A
Third option:
NPSV; N + 2 = P; P + 3 = S; S + 3 = V
Fourth option:
HJMQ; H + 2 = J; J + 3 = M; M + 4 = Q
So, the third option is different from the other options as the difference between the letters is 2, 3, 3 instead of 2, 3, 4. Hence, the third option is correct.
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