Correct Answer: ifgie

Solution : Given:
gfe_ig_eii_fei_gf_ii

To fill the series we have to divide the series→gfe_i / g_eii / _fei_ / gf_ii
Let's check each option –
First option: eifgi; gfe e i / g i eii / f fei g / g f i ii (No repeated pattern has been found.)
Second option: figie; gfe f i / g i eii / gfei i / gf e ii (No repeated pattern has been found.)
Third option: ifgie; gfe i i / g f eii / g fei i / gf e ii (gfeii is repeated in the series.)
Fourth option: ifige; gfe i i / g f eii / i fei g / gf e ii (No repeated pattern has been found.)

So, the series becomes→gfeiigfeii g feiigfeii. Hence, the third option is correct.