Question : Directions: In the following question, you have to identify the correct response from the given premises stated according to the following symbols.
If – stands for division, + stands for multiplication, ÷ stands for subtraction and × stands for addition, then which of the following equations holds true?
Option 1: 4 × 5 + 9 – 3 ÷ 4 = 15
Option 2: 4 – 5 × 9 + 3 ÷ 4 = 32
Option 3: 4 – 5 ÷ 18 × 3 – 4 = 70
Option 4: 4 ÷ 5 + 9 – 3 ÷ 4 = 81
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 4 × 5 + 9 – 3 ÷ 4 = 15
Solution :
Given:
– stands for division, + stands for multiplication, ÷ stands for subtraction, and × stands for addition.
Let's check the options –
First option:
4 × 5 + 9 – 3 ÷ 4 = 15
On interchanging the symbols, the equation becomes –
4 + 5 × 9 ÷ 3 – 4 = 15
Solving the L.H.S. of the equation –
= 4 + 5 × 3 – 4
= 4 + 15 – 4
= 19 – 4
= 15
Second option:
4 – 5 × 9 + 3 ÷ 4 = 32
On interchanging the symbols, the equation becomes –
4 ÷ 5 + 9 × 3 – 4 = 32
Solving the L.H.S. of the equation –
= 0.8 + 9 × 3 – 4
= 0.8 + 27 – 4
= 27.8 – 4
= 23.8 ≠ 32
Third option:
4 – 5 ÷ 18 × 3 – 4 = 70
On interchanging the symbols, the equation becomes –
4 ÷ 5 – 18 + 3 × 4 = 70
Solving the L.H.S. of the equation –
= 0.8 – 18 + 3 × 4
= 0.8 – 18 + 12
= 12.8 – 18
= –5.2 ≠ 70
Fourth option:
4 ÷ 5 + 9 – 3 ÷ 4 = 81
On interchanging the symbols, the equation becomes –
4 – 5 × 9 ÷ 3 – 4 = 81
Solving the L.H.S. of the equation –
= 4 – 5 × 3 – 4
= 4 – 15 – 4
= –15 ≠ 81
So, only the first option satisfies the given equation. Hence, the first option is correct.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
