Question : Directions: In the given question, select the related letter cluster from the given alternatives.
FLRX : EJOT :: CKTY : ?
Option 1: BIQV
Option 2: DIPQ
Option 3: DHQU
Option 4: BIQU
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Correct Answer: BIQU
Solution :
Given:
FLRX : EJOT :: CKTY : ?
Subtract consecutive natural numbers from the place value of each letter of
FLRX to obtain the code –
F – 1 = E; L – 2 = J; R – 3 = O; X – 4 = T
Thus, FLRX is coded as EJOT.
Similarly, follow the same pattern for CKTY –
C – 1 = B; K – 2 = I; T – 3 = Q; Y – 4 = U
Thus, CKTY is coded as BIQU. Hence, the fourth option is correct.
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