Question : Directions: Joel and Tom were travelling from town X to town Y which was 210 km apart. Joel set off 1 hour and 15 minutes later than Tom but arrived 15 minutes earlier. If the average speed of Tom was 42 km/h, find the average speed of Joel.
Option 1: 50 km/h
Option 2: 60 km/h
Option 3: 65 km/h
Option 4: 70 km/h
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 60 km/h
Solution :
Given:
Distance between town X and town Y = 210 km
Average speed of Tom = 42 km/h
Time taken by Tom = Distance ÷ Speed
= 210 ÷ 42
= 5 hours
Here, Joel started 1hr 15 mins late and arrived 15 mins earlier.
Thus, the time taken by Joel
= 5 hrs – 1hr 15mins – 15mins
= (5 × 60) – (1 × 60 + 15) – 15
= 300 – 75 – 15
= 300 – 90
= 210 mins
Now, convert minutes into hours –
= 210 ÷ 60
= 3.50 hrs
Average speed = Distance ÷ Time
= 210 ÷ 3.5
= 60 km/h
So, the average speed of Joel is 60 km/h. Hence, the second option is correct.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.