Question : Directions: Select the correct combination of the mathematical signs that can be filled to balance the following equation:
12 _ 4 _ 2 _ 2 _ 5 _ 3
Option 1: +, =, ÷, ×, +
Option 2: ÷, ×, +, =, +
Option 3: ÷, ×, –, =, ×
Option 4: ÷, ×, =, +, +
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Correct Answer: ÷, ×, +, =, +
Solution :
Given:
12 _ 4 _ 2 _ 2 _ 5 _ 3
Replace the given symbols in the options one by one with the original symbols in the given equation.
First option:
+, =, ÷, ×, +
12 + 4 = 2 ÷ 2 × 5 + 3
L.H.S. = 12 + 4 = 16
R.H.S. = 2 ÷ 2 × 5 + 3 = 1 × 5 + 3 = 5 + 3 = 8
L.H.S. ≠ R.H.S.
Second option:
÷, ×, +, =, +
12 ÷ 4 × 2 + 2 = 5 + 3
L.H.S. = 12 ÷ 4 × 2 + 2 = 3 × 2 + 2 = 6 + 2 = 8
R.H.S. = 5 + 3 = 8
L.H.S. = R.H.S.
Third option:
÷, ×, –, =, ×
12 ÷ 4 × 2 – 2 = 5 × 3
L.H.S. = 12 ÷ 4 × 2 – 2 = 3 × 2 – 2 = 6 – 2 = 4
R.H.S. = 5 × 3 = 15
L.H.S. ≠ R.H.S.
Fourth option:
÷, ×, =, +, +
12 ÷ 4 × 2 = 2 + 5 + 3
L.H.S. = 12 ÷ 4 × 2 = 3 × 2 = 6
R.H.S. = 2 + 5 + 3 = 10
L.H.S. ≠ R.H.S.
So, the second option satisfies the given equation. Hence, the second option is correct.
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