Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term and the sixth term is related to the fifth term.
U39R : P118M : F18A : ? :: G72K : B217F
Option 1: C55V
Option 2: A55W
Option 3: A55V
Option 4: B55U
Correct Answer: A55V
Solution :
Given:
U39R : P118M : F18A : ? :: G72K : B217F
Subtract 5 in the place value of the first and third letter respectively, multiply the middle number by 2 and add the resultant to the addition of the number and 1 in U39R, to obtain the required code –
Like, U39R : P118M→U – 5 = P; (39 × 2) + (39 + 1) = 118; R – 5 = M
Thus, U39R is coded as P118M.
And, G72K : B217F→G – 5 = B; (72 × 2) + (72 + 1) = 217; K – 5 = F
Thus, G72K is coded as B217F.
Similarly, follow the same pattern for F18A : ?→F – 5 = A; (18 × 2) + (18 + 1) = 55; A – 5 = V
Thus, F18A is coded as A55V. Hence, the third option is correct.
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