Correct Answer: KMP

Solution : Given:
BCO : OBC :: MPK : ?

BCO : OBC; The pattern follows as the third letter is written at the first position, followed by the first and second letters to obtain the required code.

Let's check the options –
First option: PMK→MPK : ?
After moving the positions as per the given pattern the letter cluster becomes ⇒ KMP ≠ PMK
Second option: PKM→MPK : ?
After moving the positions as per the given pattern the letter cluster becomes ⇒ KMP ≠ PMK
Third option: KMP→MPK : ?
After moving the positions as per the given pattern the letter cluster becomes ⇒ KMP = MPK
Fourth option: LMM→MPK : ?
After moving the positions as per the given pattern the letter cluster becomes ⇒ KMP ≠ LMM

So, only the third option satisfies the given pattern. Hence, the third option is correct.