Question : Directions: The following bar graph shows the production of fertilizers (in lakh tonnes) by a company, in six consecutive years. Study the graph and answer the questions.
The difference between the average production of fertilizers in the first three years and the average production in the last three years (in lakh tonnes) is:
Option 1: $2\frac{1}{3}$
Option 2: $8\frac{1}{3}$
Option 3: $4\frac{1}{6}$
Option 4: $3\frac{1}{3}$
Correct Answer: $8\frac{1}{3}$
Solution :
Based on the given graph in question,
Production of fertilizers in 1995 = 70
Production of fertilizers in 1996 = 80
Production of fertilizers in 1997 = 90
Production of fertilizers in 1998 = 80
Production of fertilizers in 1999 = 60
Production of fertilizers in 2000 = 75
Sum of production of fertilizers in the first three years = 70 + 80 + 90 = 240 lakh tonnes
Sum of production of fertilizers in the last three years = 80 + 60 + 75 = 215 lakh tonnes
Average production of fertilizers in the first three years = $\frac{240}{3}$ lakh tonnes
Average production of fertilizers in the last three years = $\frac{215}{3}$ lakh tonnes
The difference in the average production of fertilizers in the first three and last three years
= $\frac{240}{3}-\frac{215}{3} = \frac{25}{3} = 8\frac{1}{3}$ lakh tonnes
Hence, the correct answer is $8\frac{1}{3}$.
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