Question : Directions: The price of an article has been reduced by 25%. To restore the original price, the new price must be increased by?
Option 1: $11\frac{1}{9}\%$
Option 2: $66\frac{2}{3}\%$
Option 3: $9\frac{1}{11}\%$
Option 4: $33\frac{1}{3}\%$
Correct Answer: $33\frac{1}{3}\%$
Solution : Let the price of an article be Rs 100. The price of an article after reduction = 100 – 25 % of 100 The price of an article after reduction = 100 – ($\frac{25}{100}$ × 100) = 100 – 25 = Rs 75
Now, let the percentage increase in the price be x %. So, according to the question – ⇒ 75 + x % of 75 = 100 ⇒ x % of 75 = 100 – 75 = 25 ⇒ $\frac{x}{100}$ × 75 = 25 ⇒ x = $\frac{25 × 100}{75}$ ⇒ x = $33\frac{1}{3}\%$
So, the price must be increased by $33\frac{1}{3}\%$. Hence, the fourth option is correct.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : If the numerator of a fraction is increased by 60% and the denominator is increased by 40%, then the resultant fraction is $\frac{16}{63}$. The original fraction is:
Question : The price of almonds is increased by 10%. By what percentage should the consumption be decreased so that the expenditure remains the same?
Question : Find the HCF of $\frac{11}{25}, \frac{9}{20}, \frac{16}{15}$, and $\frac{10}{33}$.
Question : The price of a car is first increased by 35% and after that, the price is decreased by 25% due to a reduction in sales. What is the net percentage change in the final price of the car?
Question : If the diameter of a sphere is reduced to its half, then the volume would be:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile