Question : Directions: Town A and Town B were 600 km apart. Joshua left town A for town B and travelled at an average speed of 65 km/h. At the same time, Menon left town B for town A. The two of them met 5 hours later. Find Menon's average speed.
Option 1: 55 km/h
Option 2: 60 km/h
Option 3: 65 km/h
Option 4: 120 km/h
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Correct Answer: 55 km/h
Solution : Given: Distance between town A and town B = 600 km Average speed of Joshua = 65 km/h Time taken = 5 hours
So, Joshua covered a distance of = Speed × Time = 65 × 5 = 325 km Distance to be covered by Menon – = 600 – 325 = 275 km Therefore, the average speed of Menon – = Distance ÷ Time = 275 ÷ 5 = 55 km/h
Hence, the first option is correct.
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