Question : Directions: Which of the following numbers will replace the question mark (?) in the given series?
$96,12, \frac{3}{2}, ?, \frac{3}{128}$
Option 1: $\frac{3}{12}$
Option 2: $\frac{1}{128}$
Option 3: $\frac{3}{64}$
Option 4: $\frac{3}{16}$
Correct Answer: $\frac{3}{16}$
Solution :
Given:
$96,12, \frac{3}{2}, ?, \frac{3}{128}$
Multiply the previous term by $\frac{1}{8}$ to obtain the missing term in the given series.
$96×\frac{1}{8}=12;12×\frac{1}{8}=\frac{3}{2}; \frac{3}{2}×\frac{1}{8}=\frac{3}{16};\frac{3}{16}×\frac{1}{8}=\frac{3}{128}$
So, $\frac{3}{16}$ is the missing term in the given series. Hence, the fourth option is correct.
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