Question : Directions: Which two numbers, from amongst the given options, should be interchanged to make the given equation correct?
62 – 20 + (28 ÷ 7) – [(√4) × 8 ] + 22 = 40
Option 1: 6 and 8
Option 2: 7 and 2
Option 3: 2 and 8
Option 4: 20 and 8
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Correct Answer: 6 and 8
Solution :
Given:
6
2
– 20 + (28 ÷ 7) – [(√4) × 8 ] + 2
2
= 40
Interchange the numbers according to the given options.
Let's check each option –
First option:
6 and 8
8
2
– 20 + (28 ÷ 7) – [(√4) × 6 ] + 2
2
= 40
= 44 + 4 – [2 × 6 ] + 4
= 48 – 12 + 4
= 40
Second option:
7 and 2
6
2
– 20 + (28 ÷ 2) – [(√4) × 8 ] + 7
2
= 40
= 16 + 14 – 16 + 49
= 63 ≠ 40
Third option:
2 and 8
6
2
– 20 + (28 ÷ 7) – [(√4) × 2 ] + 8
2
= 40
= 16 + 4 – 4 + 64
= 80 ≠ 40
Fourth option:
20 and 8
6
2
– 8 + (28 ÷ 7) – [(√4) × 20 ] + 2
2
= 40
= 28 + 4 – 40 + 4
= – 4 ≠ 40
Therefore, only the first option satisfies the R. H.S. of the equation. Hence, the first option is correct.
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