Question : Directions: Which two numbers should be interchanged, to make the given equation correct?
192 ÷ 12 × 6 + 16 – 18 = 66
Option 1: 16 and 18
Option 2: 16 and 6
Option 3: 6 and 18
Option 4: 16 and 12
Correct Answer: 16 and 12
Solution :
Given:
192 ÷ 12 × 6 + 16 – 18 = 66
Replace the given numbers in the options one by one with the original numbers in the given equation.
First option:
16 and 18
192 ÷ 12 × 6 + 16 – 18 = 66
= 192 ÷ 12 × 6 + 18 – 16 = 66
= 16 × 6 + 18 – 16
= 98
≠
66
Second option:
16 and 6
192 ÷ 12 × 6 + 16 – 18 = 66
= 192 ÷ 12 × 16 + 6 – 18 = 66
= 16 × 16 + 6 – 18
= 256 + 6 – 18
= 244
≠
66
Third option:
6 and 18
192 ÷ 12 × 6 + 16 – 18 = 66
= 192 ÷ 12 × 18 + 16 – 6 = 66
= 16 × 18 + 16 – 6
= 288 + 16 – 6
= 298
≠
66
Fourth Option:
16 and 12
192 ÷ 12 × 6 + 16 – 18 = 66
= 192 ÷ 16 × 6 + 12 – 18 = 66
= 12 × 6 + 12 – 18
= 72 + 12 – 18
= 66
Here, only the fourth option satisfies the R.H.S. of the given equation. Hence, the fourth option is correct.
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