Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 14 × 6 ÷ 12 + 15 – 9 = 203
Option 1: 15 and 6, + and ÷
Option 2: 12 and 15, – and ×
Option 3: 12 and 9, ÷ and –
Option 4: 14 and 6, ÷ and ×
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Correct Answer: 15 and 6, + and ÷
Solution : Given: 14 × 6 ÷ 12 + 15 – 9 = 203
Interchange the signs and numbers given in the equation with the assigned signs and numbers in the options one by one – First option: 15 and 6, + and ÷ On interchanging the signs and numbers, we get – ⇒ 14 × 15 + 12 ÷ 6 – 9 = 203 Solving the L.H.S. of the equation – = 14 × 15 + 12 ÷ 6 – 9 = 14 × 15 + 2 – 9 = 210 + 2 – 9 = 212 – 9 = 203 Second option: 12 and 15, – and × On interchanging the signs and numbers, we get – ⇒ 14 – 6 ÷ 15 + 12 × 9 = 203 Solving the L.H.S. of the equation – = 14 – 6 ÷ 15 + 12 × 9 = 14 – 0.4 + 12 × 9 = 14 – 0.4 + 108 = 122 – 0.4 = 121.6 ≠ 203 Third option: 12 and 9, ÷ and – On interchanging the signs and numbers, we get – ⇒ 14 × 6 – 9 + 15 ÷ 12 = 203 Solving the L.H.S. of the equation – = 14 × 6 – 9 + 15 ÷ 12 = 14 × 6 – 9 + 1.25 = 84 – 9 + 1.25 = 85.25 – 9 = 76.25 ≠ 203 Fourth option: 14 and 6, ÷ and × On interchanging the signs and numbers, we get – ⇒ 6 ÷ 14 × 12 + 15 – 9 = 203 Solving the L.H.S. of the equation – = 6 ÷ 14 × 12 + 15 – 9 = 0.43 × 12 + 15 – 9 = 5.16 + 15 – 9 = 20.16 – 9 = 11.16 ≠ 203
Here, only the first option satisfies the R.H.S. of the given equation. Hence, the first option is correct.
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