Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 60 × 3 + 660 ÷ 6 – 20 = 290
Option 1: 6 and 660; × and ÷
Option 2: 20 and 6; + and –
Option 3: 20 and 60; + and ×
Option 4: 20 and 660; + and ÷
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Correct Answer: 20 and 60; + and ×
Solution : Given: 60 × 3 + 660 ÷ 6 – 20 = 290
Let's check the given options – First option: 6 and 660; × and ÷ On interchanging, the mathematical signs and numbers, we get – 60 ÷ 3 + 6 × 660 – 20 = 290 Solving the L.H.S. of the given equation – = 60 ÷ 3 + 6 × 660 – 20 = 20 + 6 × 660 – 20 = 20 + 3960 – 20 = 3980 – 20 = 3960 ≠ 290 Second option: 20 and 6, + and – On interchanging, the mathematical signs and numbers, we get – 60 × 3 – 660 ÷ 20 + 6 = 290 Solving the L.H.S. of the given equation – = 60 × 3 – 660 ÷ 20 + 6 = 60 × 3 – 33 + 6 = 180 – 33 + 6 = 186 – 33 = 153 ≠ 290 Third option: 20 and 60, + and × On interchanging, the mathematical signs and numbers, we get – 20 + 3 × 660 ÷ 6 – 60 = 290 Solving the L.H.S. of the given equation – = 20 + 3 × 660 ÷ 6 – 60 = 20 + 3 × 110 – 60 = 20 + 330 – 60 = 350 – 60 = 290 = R.H.S. Fourth option: 20 and 660, + and ÷ On interchanging, the mathematical signs and numbers, we get – 60 × 3 ÷ 20 + 6 – 660 = 290 Solving the L.H.S. of the given equation – = 60 × 3 ÷ 20 + 6 – 660 = 9 + 6 – 660 = 14 – 660 = – 646 ≠ 290
So, only the third option satisfies the R.H.S. of the given equation. Hence, the third option is correct.
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