1854 Views

electrical conductivity of a semiconductor


Avijit Singha 7th Oct, 2020
Answer (1)
Tapas Kumar Singh 7th Oct, 2020
Hello dear student

Let's derive the expression the expression for conductivity of semiconductor.

In a Semi-Conductor of length (L) and area of Cross-Section A.
Let n e and n h be the no. of electrons and holes with drift velocities V e and V h respectively.

So, the total current in the semi-conductor will be the sum of current due to electrons as well as holes,

i.e. I = I e + I h (i)

As we know that

I = n e A V d

\I e = n e e A V e

And I h = n h e A V h

I = n e e A V e + n h e A V h

I = eA[n e V e + n h v h ]

I/A = e[n e V e + n h v h ] (2)

As we know that

E = V/l (in magnitude)

Also, R = l/A

Or = RA/l

Where is resistivity and R is resistance

Or E/ = (V/l)/

Or E/ = (V/l)l/ RA

E/ = (V/RA)

E/ = I/A (3)

Put (3) in (2) we get,

E/ = e[n e V e + n h v h ]

I/ = e / E[n e V e + n h v h ]

= e [n e V e /E + n h v h /E] ( = Conductivity)

Here, mobility (m) = Drift vel./ Electric field

= e [n e m e + n h m h ]



This is the derivation and expression for the conductivity of a semiconductor.


Hope that's helpful


Best of luck

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida M.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
JIIT Online MBA
Apply
Apply for Online MBA from Jaypee Institute of Information Technology
VIT - VITEEE 2026
Apply
National level exam conducted by VIT University, Vellore | Ranked #16 by NIRF for Engg. | NAAC A++ Accredited
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books