Equal masses of h2 o2 and methane have been taken in a container of volume v and temperature 27 degree Celsius the ratio of volume
Let the mass of each gas be given by w.
So no. Of moles of H2 are= w/2
No of moles of O2 are= w/32
No.of moles of CH4 are= w/16
Therefore volume of H2 = w/2 * 22.4L
Volume of O2 is= w/32 * 22.4L
Volume of CH4 is given as= w/16 * 22.4L
So the ratio will be 1/2 : 1/32 : 1/16 = 16: 1 : 2