equal weight of methane and sulphur axide are present in a vessel of litre capacity what is the partical pressure of sulphur oxide if the total pressure of the mixure of gasses is 12 atm
Hello There,
First of all calculate the total number of moles using the ideal gas law. Here as you have not mentioned temperature I have assumed it as room temperature.
BY formula n = PV/RT you'll get total moles = 0.5
Now calculate the total mass by the formula total moles = moles of ch4 + moles of SO
I.e 0.5 = x/16 + x/48
By this, you'll get x = 0.5 g
Now calculate number of moles of individual component by formula n = 0.5 g / 16 for CH4 and 0.5/48 for SO.
From the obtained values of moles of CH4 and SO, calculate the Mole fraction
which is obtained as 0.75 for CH4 and 0.25 for SO.
After this,
We have for gases, Pressure fraction = Mole Fraction
i.e p1/12 = 0.75 for CH4 and 12-p1 for SO
The obtained values for partial pressure for CH4 is 9 atm and for SO is 3 atm
Good Luck!!!!
