evalute limit x tends to zero log sin x?
Answer (1)
20th Aug, 2021
Hello
hope you are doing great. As per your query I would glad to tell you that
this question can be solved by the formula log(1+x)/x when x tends to zero convert log argument(sinx) in the form of 1+x by adding and substractin 1 and then multiply numerator and denominator by sinx-1 . then whole log part will become 1 and you will be left with sinx-1 on putting x=0 the result will be -1
Comments (0)
