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find an equation of the tangent line to the parabola y=x^2 -8x+9 at the point (3,-6).


Rohith 16th Nov, 2020
Answer (1)
AKSHAYA.V.A. 16th Nov, 2020

Hello!

y = f(x) = x^2 - 8x +9

f ' (x) = 2x-8

f ' (3) = 6 - 8 = - 2 = m   ......(a)

taking tangent line into consideration (3,-6)

y - y1 = f ' (m) (x - x1) ..............( formula)

y - (-6) = (-2) ( x - 3 )    (putting 2 in place of m)

y +6 = - 2 x + 6     [(-(-)) = +]

y = - 2 x

ALL THE BEST. Hope the answer was helpful.

Thank You


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