find an equation of the tangent line to the parabola y=x^2 -8x+9 at the point (3,-6).
Answer (1)
16th Nov, 2020
Hello!
y = f(x) = x^2 - 8x +9
f ' (x) = 2x-8
f ' (3) = 6 - 8 = - 2 = m ......(a)
taking tangent line into consideration (3,-6)
y - y1 = f ' (m) (x - x1) ..............( formula)
y - (-6) = (-2) ( x - 3 ) (putting 2 in place of m)
y +6 = - 2 x + 6 [(-(-)) = +]
y = - 2 x
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