find expression for electric field due to straight uniformly charged infinite line of charge density lambda
Answer (1)
26th Mar, 2021
Hello candidate,
First take the assumption- Let us draw a gaussian cylinder of length l and radius r across the line of charge having density λc/m.
At cylindrical part of the surface electric field vector E is normal to the surface at every point and its magnitude is constant. Therefore flux through the Gaussian surface. = Flux through the curved cylindrical part of the surface. = E x 2πrl and hence, the expression for electric field is given by lambda/ 2π£r.
Hope It was helpful!!
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