Hello,

We have to find the integration of logs. sinx.dx,

Intg.( logs.sinx.dx) = clearly logs is a constant, so take it out of the integration.

= logs. intg.( sinxdx) = - logs. cosx , now we have to put the upper and lower limits as pi and 0.

So we get,

- logs. ( -1 - 1 )

= 2 .logs

Hence this is the answer of the integration.

Hope it helps you.