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Find integration of logs sin dx whose upper and lower limit are pi and zero


ankita singh 20th Jan, 2021
Answer (1)
Parmeshwar Suhag 20th Jan, 2021

Hello,

We have to find the integration of logs. sinx.dx,

Intg.( logs.sinx.dx) = clearly logs is a constant, so take it out of the integration.

= logs. intg.( sinxdx) = - logs. cosx , now we have to put the upper and lower limits as pi and 0.

So we get,

- logs. ( -1 - 1 )

= 2 .logs

Hence this is the answer of the integration.

Hope it helps you.

3 Comments
Comments (3)
20th Jan, 2021
Ans is - log2a
Reply
20th Jan, 2021
Ur ans is incrct
Reply
22nd Jan, 2021
ankita singh please write the question briefly firstly
Reply

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