Hello,
We have to find the integration of logs. sinx.dx,
Intg.( logs.sinx.dx) = clearly logs is a constant, so take it out of the integration.
= logs. intg.( sinxdx) = - logs. cosx , now we have to put the upper and lower limits as pi and 0.
So we get,
- logs. ( -1 - 1 )
= 2 .logs
Hence this is the answer of the integration.
Hope it helps you.
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