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find range y =|sin x|+|cos x|


Himalaya Das 19th Oct, 2019
Answer (1)
Ronak Gala Student Expert 19th Oct, 2019

Let f(x)=|sinx|+|cosx|.

Domain : Domain of the function f(x) will be the intersection of domains of sinx and cosx. As the domain of sinx as well as cosx is (-∞,∞), thus the domain of the funtion f(x) will the the intersection of the two domains which comes out to be (-∞,∞) that is, that x can take any real value ranging from -∞ to +∞.

Therefore, the domain is (-∞,+∞).

Range : Range of any continuous funtion lies inbetween the minimum and maximum value of that function.

For finding the minimum and maximum of the function f(x), differentiate f(x) w.r.t. x and equate it with 'zero'.

Mathematically, df(x)/dx=0

So, d(sinx+cosx)/dx=0

i.e. cosx-sinx=0

=> cosx=sinx

=> x=π/4, 5π/4, 9π/4 and so on.

Taking x=5π/4 for f(x) to be minimum, f(x)=-2/√2=-√2.

Taking x=π/4 for f(x) to be maximum, f(x)=2/√2=√2.

Thus the range of the function f(x) is [-√2,√2].

thankyou.

3 Comments
Comments (3)
4th Dec, 2020
Let me know am I correct or not?
-1<=sinx<=1 -1<=cosx<=1
If we put ||(mod) for both
0<=|sinx|<=1 0<=|cosx<|=1
Add both we get

0<=|sinx|+|cosx|<=2
So, the range is [0 2].
Reply
17th Aug, 2022
kavuru sai kiran @kavuru sai kiran is wrong as its upper bound is √2
Reply
17th Aug, 2022
Both answers are wrong as we can see upper bound is √2 but for lower bound is something above 0
Reply

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