Question : Find the angular elevation of the Sun when the shadow of a 15 metres long pole is $\frac{15}{\sqrt{3}}$ metres.
Option 1: $45^\circ$
Option 2: $60^\circ$
Option 3: $30^\circ$
Option 4: $90^\circ$
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Correct Answer: $60^\circ$
Solution :
Let $\theta$ be the angular elevation of the Sun.
Here, $\tan\theta = \frac{AB}{BC} = (15×\frac{\sqrt{3}}{15}) = \sqrt{3}$ metres
⇒ $\tan\theta = \sqrt{3}=\tan60^\circ$
⇒ $\theta = 60^\circ$
$\therefore$ The angular elevation of the Sun is $60^\circ$.
Hence, the correct answer is $60^\circ$.
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