Question : Find the area of an equilateral triangle whose sides are 16 cm.
Option 1: $60\sqrt{3}\mathrm{~cm}^2$
Option 2: $62\sqrt{3} \mathrm{~cm}^2$
Option 3: $64\sqrt{3} \mathrm{~cm}^2$
Option 4: $66\sqrt{3} \mathrm{~cm}^2$
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Correct Answer: $64\sqrt{3} \mathrm{~cm}^2$
Solution :
Length of a side of the given equilateral triangle $= 16$ cm.
As the area of an equilateral triangle is $\frac{\sqrt{3}}4a^2$ where $a$ is one side.
So, area $=\frac{\sqrt3}{4}\times 16^2 = 64\sqrt3$ cm
2
.
Hence, the correct answer is $64\sqrt{3} \mathrm{~cm}^2$.
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