find the coordinates of the point whose distance from (3 5) is 5 units and from (0 1) is 10 units
Answer (1)
10th May, 2021
Hello aspirant,
Hope you are doing well
Let the required coordinated be (x, y)
then, A (3, 5) B(x, y) C(0,1)
The distance between A(3, 5) and B(x, y) = 5 units
the distance between B(x, y) and C(0,1) =10 units.
Now, we use the formula,
x = (m1x + m2x) / (m1 + m2)
y = (m1y + m2y) / (m1 + m2)
Here, m1 and m2 is the distance between two coordinate i.e., 5, 10
and (x1, y1) = (3, 5) and x2, y2 = (0, 1)
So, x = ((5 * 0) + (10 *3 )) / ( 10 + 5 )
= 30 /15 = 2
y = ((5 *1 ) +(10 *5)) / ( 10 + 5 )
= 55 / 15 = 11/3
Hence, the coordinate is (x, y ) = (2, 11/3)
I hope this will help you.
Feel free to ask any query.
All the best.
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