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find the coordinates of the point whose distance from (3 5) is 5 units and from (0 1) is 10 units


gouravjaglan077 10th May, 2021
Answer (1)
Jainshahajal 10th May, 2021

Hello aspirant,

Hope you are doing well

Let the required coordinated be (x, y)

then, A (3, 5)  B(x, y)  C(0,1)

The distance between A(3, 5) and B(x, y) = 5 units

the distance between B(x, y) and C(0,1) =10 units.

Now, we use the formula,

x = (m1x + m2x) / (m1 + m2)

y = (m1y + m2y) / (m1 + m2)

Here, m1 and m2 is the distance between two coordinate i.e., 5, 10

and (x1, y1) = (3, 5) and x2, y2 = (0, 1)

So, x = ((5 * 0) + (10 *3 )) / ( 10 + 5 )

= 30 /15 = 2

y = ((5 *1 ) +(10 *5)) / ( 10 + 5 )

= 55 / 15 = 11/3

Hence, the coordinate is (x, y ) = (2, 11/3)

I hope this will help you.

Feel free to ask any query.

All the best.



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