Find the equation of circle passing through two points on y-axis at distance 3 from the origin having the radius 5
Answer (1)
Student Expert
18th Dec, 2018
Hello,
The general equation of a circle with center (x0,y0) and radius r is given by:
(x−x0)2+(y−y0)2=r2
You are looking for the circle which intersects the points (0,3)(0,3) and (0,−3)(0,−3), whose radius is 55. To find the center of the circle, you need to find the point (x0,y0)(x0,y0) such that
√(x0−0)2+(y0−3)2 = √ (x0−0)2+(y0+3)2 = 5
Note that this center must necessarily be located on the x-axis: (x0,y0)=(x0,0), determined by x0,−x0, each of which will define a distinct circle.
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