Question : Find the exact value of $\cos 120^{\circ}$.
Option 1: –0.5
Option 2: 0
Option 3: 0.5
Option 4: 1
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: –0.5
Solution : We know that, $\cos (90^\circ + \theta) = - \sin \theta$ So, $\cos 120^\circ = \cos (90^\circ + 30^\circ) = - \sin30^\circ =-\frac{1}{2} = -0.5$ Hence, the correct answer is –0.5.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : Find the exact value of $\cos 120°$.
Question : Find the value of $\cos 47^\circ \sec 133^\circ + \sin 44^\circ \text{cosec}\; 136^\circ $.
Question : If $0\leq\theta\leq 90^{\circ}$ and $4\cos^{2}\theta-4\sqrt{3}\cos\theta+3=0$, then the value of $\theta$ is:
Question : What is the value of $5 \sqrt{3} \cos 60^{\circ} \tan 30^{\circ}-3 \cos 0^{\circ}+3 \cos ^2 45^{\circ}+2 \sin ^2 60^{\circ}$?
Question : Find the value of $\frac{\cos^2 15^{\circ}-\sin^2 15^{\circ}}{\cos^2 145^{\circ}+\sin^2 145^{\circ}}$.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile