Find the laplace transforms of the following periodic function f(t) = t , 0
Answer (1)
4th Nov, 2020
Hi,
I hope you know the form of the Laplace Transform. I am not allowed to use images on this website, but you can find it on any Mathematics website.
Here f(t)=t, your limits will not varay from +inf to -inf but from 0 to 2.
For periodic function however it takes a different form which nothing but a highly specialized one by using certain constraints.
The answer will be like :
1/(1-e^-2s)*[-((2*e^-2s)/s)-((e^-2s)/(s^2))+1/s^2]
Hope this helps!
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