Question : Find the least value of (A + B) if the number 27B58A4 is completely divisible by 88.
Option 1: 5
Option 2: 2
Option 3: 4
Option 4: 7
Correct Answer: 2
Solution :
A number is divisible by 88 if it is divisible by both 8 and 11 because 88 is the product of 8 and 11.
For a number to be divisible by 8, the last three digits must be divisible by 8.
The given number is 27B58A4
So, 8A4 must be divisible by 8.
The least possible value of A is 2.
So, the number becomes 27B5824.
For a number to be divisible by 11, the difference between the sum of digits at odd places and the sum of digits at even places must be either 0 or a multiple of 11.
So, (2 + B + 8 + 4) – (7 + 5 + 2) = 14 + B – 14 = B should be a multiple of 11.
Thus, the least possible value of B is 0.
So, the least value of (A + B) = 2 + 0 = 2
Hence, the correct answer is 2.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
