Question : Find the mean proportion between $(6+\sqrt{8})$ and $(3-\sqrt{2})$.
Option 1: $2 \sqrt{12}$
Option 2: $\sqrt{14}$
Option 3: $(6-\sqrt{8})$
Option 4: $\sqrt{15}-7$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: $\sqrt{14}$
Solution :
The mean proportion between $(6+\sqrt{8})$ and $(3-\sqrt{2})$ is:
$\sqrt{(6+\sqrt{8})(3-\sqrt{2})}$
$=\sqrt{18-6\sqrt{2}+3\sqrt{8}-\sqrt{16}}$
$=\sqrt{18-6\sqrt{2}+6\sqrt{2}-4}$
$=\sqrt{14}$
Hence, the correct answer is $\sqrt{14}$.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates BrochureYour Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.