Find the point on the conic l/r=1-cos(thita) which has the smallest radius vector.
Hello candidate,
K=|(r^2+2(r')^2-rr'')| / (r^2+2(r')^2)^(3/2), the radius of curvature is given by 1/K.
But in order to completely solve such mathematical expressions there are limited answering options, and so it's not possible on my part to provide you with the exact solution because of such limitation.
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