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Find the range of x^2/1+x^2.kkko
Answer (1)
WWe know that x² >= 0 for all x€R
Therefore 1+x²>= 1 for all x€R
Thus the denominator is always greater than the numerator. i. e. 1+x²>x² so,
x²÷(1+x²) is always less than 1.Also, It is never equal to 1.
At x=0, the value of expression is 0.
Thus the required Range of function is [0, 1).
Hope you get it.
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