Find the sum of first 15 multiples of 8
Answer (1)
22nd Nov, 2024
The first 15 multiples of 8 are 8,16,24,32,40,48,56,64,72,80,88,96,104,112,120. As the difference between two consecutive multiple is 8, so they are forming a. Arithmetic progression.
Here a=8.
d= 8
Sum of first 15 multiples is given by Sn = n/2[ 2a +( n-1)d]
Putting value of a, d and n
Sn = 15/2[ 2×8+ (15-1)8]
Sn = 960
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