Question : Find the value of $\sin (50^{\circ} + A) – \cos (40^{\circ} - A)$.
Option 1: 2
Option 2: 0
Option 3: –1
Option 4: 1
Answer (1)
23rd Jan, 2024
Correct Answer: 0
Solution :
We know, $\sin (90^{\circ}-A)=\cos A$
$\sin (50^{\circ} + A) – \cos (40^{\circ} – A)$
$=\sin (50^{\circ} + A) – \cos (90^{\circ}–(50^{\circ} + A))$
$=\sin (50^{\circ} + A) – \sin (50^{\circ} + A)$
$=0$
Hence, the correct answer is 0.
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