Question : Find the value of $\frac{(243)^{\frac{n}{5}}\times 3^{2n+1}}{9^{n}\times 3^{n-1}}$.
Option 1: 3
Option 2: 9
Option 3: 27
Option 4: 4
Correct Answer: 9
Solution : Consider, $\frac{(243)^{\frac{n}{5}}\times 3^{2n+1}}{9^{n}\times 3^{n-1}}$ $=\frac{((3)^5)^{\frac{n}{5}}\times 3^{2n+1}}{((3)^2)^{n}\times 3^{n-1}}$ $=\frac{3^n\times3^{2n+1}}{3^{2n}\times3^{n-1}}$ $=\frac{3^{n+2n+1}}{3^{2n+n-1}}$ $=\frac{3^{3n}\times 3}{3^{3n}\times3^{-1}}$ $=3 \times 3$ $=9$ Hence, the correct answer is 9.
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Question : The value of $\frac{(243)^\frac{n}{5}\times 3^{2n+1}}{9^{n}\times 3^{n-1}}$ is:
Option 3: 6
Option 4: 12
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}-\frac{3}{4}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{25}{6}$
Option 2: $\frac{14}{3}$
Option 3: $\frac{17}{9}$
Option 4: $\frac{49}{12}$
Question : A student was asked to find the value of $\left[(\frac{4}{9} \div \frac{3}{5} \div \frac{3}{2}) \times \frac{9}{25}\right] ×{\left[\frac{2}{3} \text { of } \frac{4}{9} \div\left(3 \times \frac{3}{5} \text { of } \frac{4}{5}\right)\right]}{\frac{2}{3} \div \frac{3}{4} \text { of } 6}$ His answer was $\frac{2}{9}$. What is the difference between his answer and the correct answer?
Option 1: $\frac{1}{12}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{24}$
Option 4: $\frac{1}{6}$
Question : The value of $\frac{5-2 \div 4 \times[5-(3-4)]+5 \times 4 \div 2 \text { of } 4}{4+4 \div 8 \text { of } 2 \times(8-5) \times 2 \div 3-8 \div 2 \text { of } 8}$ is:
Option 1: $\frac{9}{8}$
Option 2: $\frac{9}{4}$
Option 3: $\frac{15}{32}$
Option 4: $\frac{89}{4}$
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{29}{6}$
Option 2: $\frac{17}{9}$
Option 3: $\frac{14}{3}$
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