Question : Find the value of $a$ in the following equation. (Given $a<10 $)
$\frac{(187 \div 17 \times a-3 \times 3)}{\left(8^2-9 \times 7+a^2\right)}=1$
Option 1: 2
Option 2: 1
Option 3: 4
Option 4: 3
Correct Answer: 1
Solution :
$\frac{(187 \div 17 \times a-3 \times 3)}{\left(8^2-9 \times 7+a^2\right)}=1$
$⇒\frac{(11a-9)}{\left(a^2+1\right)}=1$
$⇒11a - 9 = a^2 + 1$
$⇒a^2 - 11a + 10 = 0$
$⇒(a - 10)(a - 1) = 0$
$⇒a = 10$ and $a = 1$
Since $a<10$
So, $a = 1$
Hence, the correct answer is 1.
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