Find the volume of oxygen obtained on decomposition of 200gm of potassium chlorate ( KClO3 )at STP.
Answer (1)
8th Jan, 2021
Hello student,
Here's a solution to your query :
We must calculate how many moles of potassium chlorate reacted
Use the formula moles=given mass / molar mass
The mass of the reactant in the question is 200g . The molar mass of the reactant is 158.034gmol−1
200 / 158.034=1.26555mol of the reactant.
Ratio - 2:1
Therefore, 1.26555 / 2=0.632775mol of oxygen is produced.
Answer : The mass of produced oxygen is 20.2475g.
Thanks.
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