Question : Find the volume of the largest right circular cone that can be cut out from a cube whose edge is $3 \frac{1}{2}$ cm, correct to two places of decimals (use $\pi=\frac{22}{7}$).
Option 1: $13.21 \mathrm{~cm}^3$
Option 2: $21.31 \mathrm{~cm}^3$
Option 3: $11.23 \mathrm{~cm}^3$
Option 4: $12.13 \mathrm{~cm}^3$
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $11.23 \mathrm{~cm}^3$
Solution : Given: The edge of the cube = $3\frac{1}{2}=\frac{7}{2}$ cm, this will be the altitude of the cone, $h$. Now, the radius of the circular cone $=r=\frac{\frac{7}{2}}{2}=\frac{7}{4}$ The volume of cone, V = $\frac{1}{3}\pi r^2h$ ⇒ V = $\frac{1}{3}×\frac{22}{7}×\frac{7}{4}×\frac{7}{4}×\frac{7}{2}$ ⇒ V = $\frac{539}{48}$ ⇒ V = 11.23 cm 3 Hence, the correct answer is 11.23 cm 3 .
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The diameter of a sphere is 14 cm, then the volume of this sphere is (use $\pi=\frac{22}{7}$ ):
Question : If a right circular cone of height 24 cm has the circumference of its base 42$\pi$ cm, then the volume of the cone is: (Use $\pi=\frac{22}{7}$)
Question : The area of a circle whose radius is the diagonal of a square whose area is $4\;\mathrm{cm^2}$ is:
Question : Find the volume of a solid sphere whose diameter is 42 cm. (Use $\pi=\frac{22}{7}$)
Question : The curved surface area of a right circular cone of diameter $42 \ \text{cm}$ is $990 \ \text{cm}^2$. What is the slant height (in${\ \text{cm}})$ of the cone? [Use $\pi=\frac{22}{7}$]
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile