Question : Find the weight of a cylindrical iron container with a base of radius 12.6 cm and height is 4 m, where the weight of 1 cm2 of iron is 2 grams.
Option 1: 299.284 kg
Option 2: 199.584 kg
Option 3: 399.168 kg
Option 4: 499.482 kg
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Correct Answer: 399.168 kg
Solution : The radius of the cylinder, $r$ = 12.6 cm Height, $h$ = 4 m = 400 cm Volume of a cylinder = $\pi r^2 h=\frac{22}{7}×(12.6)^2×400\ \text{cm}^2$ The weight of 1 cm 2 of iron is 2 grams. Total weight of the iron = $\frac{22}{7}×(12.6)^2×400×2=399168\ \text{gram}=399.168\ \text{kg}$ Hence, the correct answer is 399.168 kg.
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