3 Views

Question : Find the weight of a cylindrical iron container with a base of radius 12.6 cm and height is 4 m, where the weight of 1 cm2 of iron is 2 grams.

Option 1: 299.284 kg

Option 2: 199.584 kg

Option 3: 399.168 kg

Option 4: 499.482 kg


Team Careers360 8th Jan, 2024
Answer (1)
Team Careers360 12th Jan, 2024

Correct Answer: 399.168 kg


Solution : The radius of the cylinder, $r$ = 12.6 cm
Height, $h$ = 4 m = 400 cm
Volume of a cylinder = $\pi r^2 h=\frac{22}{7}×(12.6)^2×400\ \text{cm}^2$
The weight of 1 cm 2 of iron is 2 grams.
Total weight of the iron = $\frac{22}{7}×(12.6)^2×400×2=399168\ \text{gram}=399.168\ \text{kg}$
Hence, the correct answer is 399.168 kg.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books