For a concave lens the distance between image and object is 10cm and magnification is 1/4. Focal length of the lens is
hiii,
Here is the solution to the question
Distance between object and image = 10 cm
Magnification = height of image / height of object = v/u
M= 1/4 (given)
m= v/u =1/4
u = 4v
u-v = 10cm
so,
4v-v = 10 cm
v= 10/3 cm
hence u =40/3 cm
now applying the lens formula
1/f = 1/v -1/u
= -3/10 + 3/40
= - 4.4 cm
therefore the focal length is -4.4cm
I hope you understand the solution.
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Thank you!!!