For a first order reaction it's frequency factor is 2×10 to the power 12/s and threshold energy is 110.8 kJ/mole.At what temperature the half life period will be 38.5 mins, if the average energy of reactants is 20.3 kJ/mol
Answer (1)
24th Nov, 2020
Hello,
We know that,
t(1/2)=(ln*ln)/k
k=(ln*ln)/38.5*60
k = 3 * 10^-4 s^-1
k = A *e^-(E/RT)
3*10^-4 = 2*10^2 * e^-(E/RT)
ln(1.5)-16ln(10)= -E/RT
T=E/(R*36.43)
and E =110.8-20.3 = 90.5 *10^3 J
therefore T = (90.5*10^3) / (8.314*36.43) = 298 K
Hope this helps!
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