for a particle performing shm square x by dt square minus 4pi square equal to 0 find the time period
Hello Student,
For a particle executing SHM , it's acceleration can be expressed in the form -------- a = -ω²x or d²x/dt² = -ω²x
According to the question :
d²x/dt² = 16π²x = ω²x
from here we can find out ω which is 4 π
So Time Period = 2 π/ ω = 2 π/4 π = 0.5 sec is the answer.
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