For a reaction the energy of activation is zero,what is the value of rate constant at 300k,if k=1.6×10^6 sec^-1 at 298k.(R=8.31 J mol^-1 K^-1)
Answer (1)
Student Expert
19th May, 2020
Hey!
As we know, equation of rate of constant k is,
K = Ae^[-(Ea/RT)]
When activation energy is zero (given) then , the term
e^(-Ea/RT) becomes equal to 1.
Aluo, rate of constant does not depend on temperature, therefore k will remain same
That is
K= 1.6+10^-6 sec^1 (at 298k and 300k)
Thank you
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