Hello Alok!
I am giving the solution for this question below.
We have, 2a+ b--->c
Rate=(-1/2)(d[a]/dt) = (-d[b]/dt)
So, (d[b]/dt)= (1/2)×0.04 = 0.02M/s
If V is doubled, c is halved, so:-
Rate= (1/4)×(d[a]/dt)= (1/2)(d[b]/dt)= 0.02/2 = 0.01M/s
So, the required rate of reaction is 0.01M/s.
Hope you are clear!
Question : $\triangle \mathrm{ABC}$ is a right-angle triangle at $\mathrm{B}$. If $\tan \mathrm{A}=\frac{5}{12}$, then $\sin \mathrm{A}+\sin \mathrm{B}+\sin \mathrm{C}$ will be equal to:
Option 1: $1 \frac{5}{13}$
Option 2: $2 \frac{4}{13}$
Option 3: $3 \frac{1}{13}$
Option 4: $2 \frac{1}{13}$
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