for the following first order ordinary differential equation dy/dt=5y-6t y(0)=-2
Answer (1)
10th Jul, 2020
We are given that dy/dt = 5y - 6t
rearranging which, we get, dy = 5y.dt - 6t.dt
Integrating both sides, we get
y = 5y.t - 3(t^2) + c
Given, y(0) = -2
which gives,
-2 = 0 + 0 +c
implies C = -2
Hence, the required equation is y = 5y.t - 3(t^2) - 2.
Hope it helps.
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