force experienced by charge q moving with velocity v in a magnesium field B is given by F=qvB find the dimensions of magnetic field
Answer (1)
Hi,
Force experienced by charge q moving with velocity v in a magnesium field B is given by F=qvB using this formula we can find the dimensions of magnetic field:
F=qvB
B=F/qv
So, dimensions of B are:
[MLT ^2] / [AT][LT^-1]
[MT^-2 A^-1]
Force experienced by charge q moving with velocity v in a magnesium field B is given by F=qvB using this formula we can find the dimensions of magnetic field:
F=qvB
B=F/qv
So, dimensions of B are:
[MLT ^2] / [AT][LT^-1]
[MT^-2 A^-1]
Comments (0)
Related Questions
explain force on a moving charge
125 Views